Solve:-
$x - 2 y + 3 z = 11$
$3 x + y - z = 2$
$5 x + 3 y + 2 z = 3$

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Solution

Given,
$x - 2 y + 3 z = 11 - - - - - (1)$
$3 x + y - z = 2 - - - - - - (2)$
$5 x + 3 y + 2 z = 3 - - - - - (3)$
Multiplying (1) with 3 and then solving with (2),we get,
$10 z - 7 y = 31 - - - - - (4)$
Multiplying (1) with 5 and then solving with (3),we get,
$z - y = 4 - - - - - - (5)$
Now,multiplying (5) with 7 and then solving with (4),we get,
$=> z = 1$
Putting the value of $z$ in (5),
$y = - 3$
putting the value of $z$ and $y$ in (1),
$x = 2$

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\frac{2}{x} - \frac{3}{y} + \frac{3}{z} = 10 \frac{1}{x} + \frac{1}{y} + \frac{1}{z} = 10 \frac{3}{x} - \frac{1}{y} + \frac{2}{z} = 13

\frac{2}{x} + \frac{3}{y} + \frac{10}{z} = 4, \frac{4}{x} - \frac{6}{y} + \frac{5}{z} = 1, \frac{6}{x} + \frac{9}{y} - \frac{20}{z} = 2; x, y, z \neq 0

2 x + 3 y + 3 z = 5

x - 2 y + z = - 4

3 x - y - 2 z = 3

5 x - y - z = (- 2)

3 x + y - 2 z = (- 5)

x - y + 3 z = 14

Solve system of linear equations, using matrix method.

2x + 3y + 3z = 5

x − 2y + z = −4

3x − y − 2z = 3

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