Solve : $3 x^{2}$ - $6 x$ + $2$ = $0$

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Solution

We have,
$\begin{matrix} 3 x^{2} - 6 x + 2 = 0 3 {[x - 1]}^{2} = 1 {(x - 1)}^{2} = \frac{1}{3} x = 1 \pm \frac{1}{\sqrt{3}} \end{matrix}$

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