Solve :
$3 x^{2} - 6 x + 3 = 0$

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Solution

$3 x^{2} - 6 x + 3 = 0$
$x^{2} - 2 x + 1 = 0$
$x^{2} - x - x + 1 = 0$
$x (x - 1) - 1 (x - 1) = 0$
$(x - 1) (x - 1) = 0$
$x = 1, 1$

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\sqrt{\frac{p}{3}}

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