Solve :
$3 x - 2 y = 1$
$2 x + y = 3$

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Solution

$3 x - 2 y = 1 2 x + y = 3 y = 3 - 2 x 3 x - 2 (3 - 2 x) = 1 3 x - 6 + 4 x = 1 7 x = 7 x = 1$

$3 (1) - 2 y = 1 1 - 2 y = 1 2 y = 2 y = 1$

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Similar questions

3 x - 2 y = 1

2 x + y = 3

\frac{x + 2 y + 1}{2 x - y + 1} = 2; \frac{3 x - y + 1}{x - y + 3} = 5

3 x - 2 y = 0

2 x + y = 7

2 x - y = 3

3 x + 2 y = 8

2 x + y = 5

3 x + 2 y = 8

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