Solve: $3 x + 5 < x - 7$ , when x is a real number.

x < - 6

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x > - 6

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x < - 12

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x > - 12

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Solution

The correct option is A $x < - 6$
$3 x + 5 < x - 7$
$3 x + 5 - x - 5 < x - 7 - x - 5$
$\Rightarrow 3 x - x < - 7 - 5$
$\Rightarrow 2 x < - 12$
$\Rightarrow x < - 6$

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