Solve: $4 (2 x - 1) - 2 (x - 5) = 5 (x + 1) + 3$

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Solution

$4 (2 x - 1) - 2 (x - 5) = 5 (x + 1) + 3$

$\Rightarrow$ $8 x - 4 - 2 x + 10 = 5 x + 5 + 3$

$\Rightarrow$ $8 x = 2 x + 6 = 5 x + 8$

$\Rightarrow$ $6 x + 6 = 5 x + 8$

$\Rightarrow$ $6 x - 5 x = 8 - 6$

$\Rightarrow$ $x = 2$

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Similar questions

4 (2 x - 1) - 2 (x - 5) = 5 (x + 1) + 3

5 (x + 3) = 4 (2 x + 1)

\frac{5 x + 4}{2 x + 1} = 2

6^{x} = \frac{1}{216}

2^{x} = 4^{2 x + 1}

Find $x$ , if:

(i) $4^{2 x} = \frac{1}{32}$

(ii) $\sqrt{2^{x + 3}} = 16$

(iii) ${(\sqrt{\frac{3}{5}})}^{x + 1} = \frac{125}{27}$

(iv) ${(\sqrt[3]{\frac{2}{3}})}^{x - 1} = \frac{27}{8}$

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