Question

Solve.
$4x^2-4ax+(a^2-b^2)=0$

Answer 1

$4x^2-4ax+(a^2-b^2)=0$

$x=\frac{-(-4a)\pm \sqrt{(-4a{)}^2-4\times 4\times (a^2-b^2)}}{2\times 4}$

$x=\frac{4a\pm 1\sqrt{a^2-a^2+b^2}}{8}$

$x=\frac{a\pm b}{2}\Rightarrow x=\frac{a+b}{2}or\frac{a-b}{2}$