Solve: $5 x^{2} + 5 x = - \frac{4}{5}$

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Solution

Given equation is $5 x^{2} + 5 x + \frac{4}{5} = 0$

We have a formula for solving quadratic equation $a x^{2} + b x + c = 0$ is

$x = \frac{- b \pm \sqrt{b^{2} - 4 a c}}{2 a}$

$x = \frac{- 5 \pm \sqrt{25 - 4 \times 5 \times \frac{4}{5}}}{10}$

$x = \frac{- 5 \pm \sqrt{25 - 16}}{10}$

$x = \frac{- 5 \pm 3}{10}$

$x = \frac{- 1}{5}, \frac{- 4}{5}$

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Similar questions

l i m x \to \infty \frac{3 x^{2} + 5 x + 2}{5 x^{2} + 6 x + 1}

Factors of

$- x^{3} - 125$

(0.5)^{{log}_{3} {log}_{1 / 5} (x^{2} - \frac{4}{5})} < 1

\frac{5 x}{2} - \frac{4}{15} = \frac{5 x}{4} - \frac{2}{5}

\int \sqrt{4 + 8 x - 5 x^{2}} d x = \sqrt{5} [\frac{5 x - 4}{10 \sqrt{(5)}} \sqrt{4 + 8 x - 5 x^{2}} + \frac{18}{25} {sin}^{- 1} \frac{5 x - 4}{6}] .

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