Given equations are
5x−3y+3=0 ......(i)
6x−5y−2=0 ......(ii)
⇒5x−3y=−3 ........(iii)
⇒6x−5y=2 .........(iv)
On multiplying eq.(iii) by 6 and eq.(iv) by 5, and subtracting the final result, we get
6(5x−3y)−5(6x−5y)=−18−10
⇒30x−18y−30x+25y=−28
⇒7y=−28
⇒y=−287=−4
∴y=−4
Substitute y=−4 in eq. (iv) we get
6x−5×−4=2
⇒6x+20=2
⇒6x=2−20=−18
⇒6x=−18
⇒x=−186=−3
∴x=−3,y=−4