Solve: $63 a^{2} - 112 b^{2}$

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Solution

$63 a^{2} - 112 b^{2}$

$= 7 (9 a^{2} - 16 b^{2})$

$= 7 ((3 a)^{2} - (4 b)^{2})$

$= 7 (3 a + 4 b) (3 a - 4 b)$

$∴ 63 a^{2} - 112 b^{2} = 7 (3 a + 4 b) (3 a - 4 b)$

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