Question

Solve $6x^2-x-2=0$

Answer 1

Given $6x^2-x-2=0$
$6x^2+3x-4x-2=03x(2x+1)-2(2x+1)=0(2x+1)(3x-2)=0$
$\therefore 2x+1=0$ or $3x-2=02x=-1$ or $3x=2\therefore x=-\frac{1}{2}$ or $x=\frac{2}{3}$
$\therefore -\frac{1}{2}$ and $\frac{2}{3}$ are the roots of $6x^2-x-2=0$