Solve $7 x - 5 {x - [7 - 6 (x - 3)]} = 3 x + 1$ .

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Solution

$\begin{matrix} 7 x - 5 {x - [7 - 6 (x - 3)]} & = 3 x + 1 7 x - 5 {x - [7 - 6 x + 18]} & = 3 x + 1 7 x - 5 (x - 25 + 6 x) & = 3 x + 1 7 x - 5 (7 x - 25) & = 3 x + 1 7 x - 35 x + 125 & = 3 x + 1 - 28 x + 125 & = 3 x + 1 31 x & = 124 x & = \frac{124}{31} x & = 4 \end{matrix}$

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