Solve:
$7 x + 6 y = 13$
$2 x - 3 y = - 1$

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Solution

$7 x + 6 y = 13 \dots (1) 2 x - 3 y = - 1 2 (2 x - 3 y = - 1) 4 x - 6 y = - 2 \dots (2) (1) + (2) 7 x + 6 y + 4 x - 6 y = 13 - 2 11 x = 11 x = 1 ⟹ 7 (1) + 6 y = 13 6 y = 13 - 7 6 y = 6 y = 1 (x, y) = (1, 1)$

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Similar questions

Solve for x and y:

$6 x + 5 y = 7 x + 3 y + 1 = 2 (x + 6 y - 1)$

Solve the following systems of equations:

$\frac{1}{7 x} + \frac{1}{6 y} = 3$

$\frac{1}{2 x} - \frac{1}{3 y} = 5$

2 x + 5 y = 12

7 x + 3 y = 13

6 x + 5 y = 7 x + 3 y + 1 = 2 (x + 6 y - 1)

x + 6 y + 5 = 0 2 x + 3 y + 1 = 0

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