Solve: $8 (x - 3) - (6 - 2 x) = 2 (x + 2) - 5 (x - 5)$ ,
then $x =$

6 \frac{7}{13}

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3 \frac{7}{13}

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7 \frac{7}{13}

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4 \frac{7}{13}

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Solution

The correct option is D $4 \frac{7}{13}$
$8 (x - 3) - (6 - 2 x) = 2 (x + 2) - 5 (x - 5) 8 x - 24 - 6 + 2 x = 2 x + 4 - 5 x + 25 10 x - 30 = - 3 x + 29 13 x = 59 x = \frac{59}{13} = 4 \frac{7}{13}$

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Similar questions

\frac{2 x^{3} - 3 x^{2} + x + 1}{2 x^{3} - 3 x^{2} - x - 1} = \frac{3 x^{3} - x^{2} + 5 x - 13}{3 x^{3} - x^{2} - 5 x + 13}

| 2 x + 3 | + x = 10

| | 2 x - x^{2} + 8 | - | x^{2} + 5 | | = | 2 x + 13 |

x

x,

3 x - \frac{1}{3} = 2 (x - \frac{1}{2}) + 5

\frac{2 x - 13}{5} - \frac{x - 3}{11} = \frac{x - 9}{5} + 1

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