Question

Solve.
Q). A block of mass 0.5 kg rests on a horizontal surface. When a horizontal force of 2.0 N is applied on it, it acquires an acceleration of 3 $m{s}^{-2}$. The force of friction between the block and the horizontal surface is

Answer 1

Dear student
GIVEN;
MASS OF THE BODY = 0.5KG
FORCE APPLIED ON IT = 2N
SO ACCELERATION = FORCE /MASS = 2/0.5 = 4m/s2
BUT THE ACCELERATION OF THE OBJECT WAS FOUND TO BE 3m/s2
SO DIFFERENSE IN ACTUAL AND RESULTANT ACCELERATION = 4-3 = 1m/s2
SO THE FORCE OF FRICTION = MASS OF THE BODY X DIFFERENCE IN ACTUAL AND RESULTANT ACCELERATION
= 0.5 X 1 = 0.5N
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