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Question

Solve 1+sinAcosA+cosA1+sinA=2secA

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Solution

L.H.S=1+sinAcosA+cosA1+sinA

=(1+sinA)2+cos2AcosA(1+sinA)

=1+sin2A+cos2A+2sinAcosA(1+sinA) ............ [sin²θ+cos²θ=1]

=1+1+2sinAcosA(1+sinA)

=2(1+sinA)cosA(1+sinA)

=2cosA=2secA=R.H.S

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