Question

Solve : $\frac{2^3\times 3^4\times 4}{3\times 32}$

Answer 1

Let $a=\frac{2^3\times 3^4\times 4}{3\times 32}$

$=\frac{2^3\times 3^4\times 2^2}{3\times 2^5}$

$=\frac{2^{3+2}\times 3^4}{3\times 2^5}$ using $a^m\times a^n=a^{m+n}$

$=2^{5-5}\times 3^{4-1}$ using $\frac{a^m}{a^n}=a^{m-n}$

$=3^3$

$a=27$