Question

Solve:

$(\frac{2\times 3.0\times {10}^{-25}}{9.1\times {10}^{-31}}{)}^{}$

Answer 1

Solve:

we know,

$\frac{a^m}{a^n}=a^{m-n}$

$(\frac{2\times 3.0\times {10}^{-25}}{9.1\times {10}^{-31}}{)}^{}$

$=\frac{2\ast 3.0\ast {10}^6}{9.1}$

$=0.65934\ast {10}^6$

$=6.5934\ast {10}^7$