Question

Solve $\frac{2}{x^2}-\frac{5}{x}+2=0$ by factorization method.

Answer 1

$\frac{2}{x^2}-\frac{5}{x}+2=0$ (factorization method)

or $\frac{2-5x+2x^2}{x^2}=0$

$2-5x+2x^2=0\times x^2$

or $2x^2-5x+2=0$

$2x^2-4x-x+2=0$

$2x(x-2)-1(x-2)=0$

$(2x-1)(x-2)=0$

$\therefore x=\frac{1}{2},2$