As, 2x+23y=16 and 3x+2y=0 are not in the general form of linear equations. To make them into linear equaions,
Take 1x=u and 1y=v. The given system of equations become
2u+23v=16
⇒12u+4v=1 (i)
and, 3u+2v=0 .(ii)
Multiplying equation (ii) by 2 and subtracting from equation (i), we get
6u−1⇒u=16
Putting u=16 in (i), we get
2+4v=1⇒v=−14
Hence, x=1u=6 and y=1v=−4
So, the solution of the given system of equations is x=6,y=−4
Putting x=6,y=−4 in y=ax−4, we get
−4=6a−4⇒a=0.