Question

Solve : $\frac{2tan{30}^{\circ }}{1+{tan}^2{30}^{\circ }}$

• A. sin ${60}^{\circ }$
• B. cos ${60}^{\circ }$
• C. tan ${60}^{\circ }$
• D. cot ${60}^{\circ }$

Answer 1

The correct option is C tan ${60}^{\circ }$

We know that,

$tan\left(2A\right)=\frac{2tanA}{1+ta{n}^{2}A}$

Putting A to be ${30}^o$

We get,

$tan\left({60}^o\right)=\frac{2tan{30}^o}{1+ta{n}^2{30}^o}$

Thus, C is the correct answer.