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Byju's Answer
Standard VI
Mathematics
Formation of Algebraic Expressions
Solve: 2y + ...
Question
Solve:
2
y
+
3
3
y
+
2
=
4
y
+
5
6
y
+
7
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Solution
2
y
+
3
3
y
+
2
=
4
y
5
6
y
+
7
but denominator is non
0
,
∴
y
≠
−
2
3
,
−
7
6
(
2
y
+
3
)
(
6
y
+
7
)
=
(
4
y
+
5
)
(
3
y
+
2
)
12
y
2
+
18
y
+
14
y
+
21
=
12
y
2
+
15
y
+
8
y
+
10
∴
9
y
=
−
11
y
=
−
11
9
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0
Similar questions
Q.
Solve:
3
x
−
2
3
y
+
7
=
5
x
−
1
5
y
+
16
;
3
x
−
15
x
−
9
=
6
y
−
5
2
y
+
3
Q.
State whether True or False.
Multiply:
2
y
−
4
y
3
+
6
y
5
by
y
2
+
y
−
3
.
The answer is
6
y
7
+
6
y
6
−
22
y
5
−
4
y
4
+
14
y
3
+
2
y
2
−
6
y
.
Q.
Add the following polynomials
4
+
2
y
−
3
y
3
,
−
8
+
4
y
+
7
y
3
a
n
d
5
−
6
y
+
8
y
3
−
6
y
2
Q.
Solve:
4
y
(
3
y
2
+
5
y
−
7
)
+
2
(
y
3
−
4
y
2
+
5
)
Q.
State whether True or False.
Divide:
−
14
x
6
y
3
−
21
x
4
y
5
+
7
x
5
y
4
by
7
x
2
y
2
, then answer is
−
2
x
4
y
−
3
x
2
y
3
+
x
3
y
2
.
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