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Question

Solve : 3x25y3=2, x3+y2=136

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Solution

3x25y3=29x10y=12...(1)

x3+y2=1362x+3y=13...(2)
uatiion
Multiplying equation (1) by 3 and (2) by 10,we get
27x30y=36...(3)
20x+30y=130...(4)

Adding equation (3) and (4),we get
Gives, y=3

Using the value of y in equation (2), we get

2x+3y13=0

2x+3(3)13=0

2x=139=4

x=2

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