Solve 4x-12-2x-324x2-12x-9-6136

(4x+1)^2+(2x+3)^24x^2+12x+9=6136 20x^2+20x+104x^2+12x+9=6136 36(20x^2+20x+10)=61(4x^2+12x+9) 720x^2+720x+360=244x^2+732x+549 720x^2+720 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Proof by mathematical induction

Solve 4x+12+...

Question

Solve
$\frac{(4 x + 1)^{2} + (2 x + 3)^{2}}{4 x^{2} + 12 x + 9} = \frac{61}{36}$

Open in App

Solution

Suggest Corrections

Similar questions

\frac{(4 x + 1)^{2} + (2 x + 3)^{2}}{4 x^{2} + 12 x + 9} = \frac{61}{36}

\frac{x^{2} + 12 x - 20}{3 x - 5} = \frac{x^{2} + 8 x + 12}{2 x + 3}

\frac{10 x^{2} + 15 x + 63}{5 x^{2} - 25 x + 12} = \frac{2 x + 3}{x - 5}

\frac{{(2 x + 1)}^{2} + {(2 x - 1)}^{2}}{{(2 x + 1)}^{2} - {(2 x - 1)}^{2}} = \frac{17}{8}

\frac{\sqrt{4 x + 1} + \sqrt{x + 3}}{\sqrt{4 x + 1} - \sqrt{x + 3}} = \frac{4}{1}

\frac{{(4 x + 1)}^{2} + {(2 x + 3)}^{2}}{4 x^{2} + 12 x + 9} = \frac{61}{36}

\frac{{(3 x - 4)}^{3} - {(x + 1)}^{3}}{{(3 x - 4)}^{3} + {(x + 1)}^{3}} = \frac{61}{189}

∣ ∣ ∣ \frac{12 x}{4 x^{2} + 9} ∣ ∣ ∣ \leq 1.

{log}_{(2 x + 3)} ({6 x}^{2} + 23 x + 21) = 4 - {log}_{(3 x + 7)} ({4 x}^{2} + 12 x + 9)

- 4 x .

(2 x + 3)^{2} = 4 x^{2} + 3^{2} + 12 x

Join BYJU'S Learning Program