Question

Solve: $\frac{d}{dx}x{\sin }^{2}x$

Answer 1

$\frac{d}{dx}\left[x{\sin }^{2}x\right]=\frac{d}{dx}\left[x\right].{\sin }^{2}x+x.\frac{d}{dx}\left[{\sin }^{2}x\right]={\sin }^{2}x+2\sin x.\frac{d}{dx}\left[sinx\right].x={\sin }^{2}x+2x\cos x\sin x$