Solve:
x−15+x−22=x3+1
LCM of 5 and 3 is 10.
⇒2(x−1)+5(x−2)10=x+33
By cross multiplication,
6(x−1)+15(x−2)=10(x+3)
⇒6x−6+15x−30=10x+30
⇒6x−6+15x−30−10x−30=0
⇒6x+15x−10x−6−30−30=0
⇒11x−66=0
⇒11x=66
⇒x=6611
∴x=6