Question

Solve
$\frac{16y^2-20y+9}{8y^2+12y+21}=\frac{4y-5}{2y+3}$

Answer 1

$\frac{16y^2-20y+9}{8y^2+12y+21}=\frac{4y-5}{2y+3}$
$=>\frac{4y(4y-5)+9}{4y(2y+3)+21}=\frac{4y-5}{2y+3}$
Let $4y-5=a$ and $2y+3=b$
$=>\frac{4y\left(a\right)+9}{4y\left(b\right)+21}=\frac{a}{b}$
$=>4yab+9b=4yab+21a$
$=>9(2y+3)=21(4y-5)$
$=>18y+27=84y-105$
$=>18y-84y=-27-105$
$=>-66y=-132$
$=>y=2$