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Question

Solve: log(tan(x2))cscxdx.

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Solution

I=log(tanx2).cosecxdx

Let ln(tanx2)=t

1tanx2.sec2x2.12dx=dt

(cosx2)dx2sinx2.cos2x2=dt

dxsinx=dt

I=tdt=t22+C

I=12[ln(tanx2)]2+C

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