Question

Solve $\underset{x\to -2}{lim}\frac{(\frac{1}{x}+\frac{1}{2})}{x+2}$

Answer 1

$\underset{x\to -2}{lim}\frac{\frac{1}{x}+\frac{1}{2}}{x+2}$

$=\underset{x\to -2}{lim}\frac{\frac{x+2}{2x}}{x+2}$

$=\underset{x\to -2}{lim}\frac{1}{2x}$

$=\frac{1}{2(-2)}$

$=\frac{-1}{4}$