Solve- limx -2x4-2x3-3x2-5x-2x5-3x4-2x3-3x2-7x-2

The correct option is D 5 The expression can be written in the form lim_ x → ( 2)(x+2)(x^3 + 3x 1)(x+2)(x^4 + x^3 + 3x +1) = lim_ x → ( 2) #1 ...

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Existence of Limit

Solve: limx ...

Question

Solve:
$lim x \to - 2 \frac{x^{4} + 2 x^{3} + 3 x^{2} + 5 x - 2}{x^{5} + 3 x^{4} + 2 x^{3} + 3 x^{2} + 7 x + 2}$

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Solution

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Similar questions

\begin{matrix} lim x \to 0 \end{matrix} (\frac{x^{5} + 2 x^{4} + x^{2} + 3 x + 2}{x^{4} + {2 x}^{3} + {3 x}^{2} - 5 x - 22}) = - \frac{1}{11}

\int \frac{2 x^{3} - 3 x^{2} - 8 x - 26}{2 x^{2} - 5 x + 2} . d x

\frac{2 x^{3} - 3 x^{2} + x + 1}{2 x^{3} - 3 x^{2} - x - 1} = \frac{3 x^{3} - x^{2} + 5 x - 13}{3 x^{3} - x^{2} - 5 x + 13}

A = \frac{{3 x}^{4}}{4} - \frac{x^{4}}{2} + 5 x - 7; B = \frac{{2 x}^{3}}{3} + \frac{{3 x}^{3}}{2} - \frac{x}{6}; C = \frac{{2 x}^{4}}{3} - \frac{{3 x}^{4}}{4} + 5

B A

A = \frac{{3 x}^{4}}{4} - \frac{x^{4}}{2} + 5 x - 7; B = \frac{{2 x}^{3}}{3} + \frac{{3 x}^{3}}{2} - \frac{x}{6}; C = \frac{{2 x}^{4}}{3} - \frac{{3 x}^{4}}{4} + 5

(- A) C

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