Question

Solve $\underset{x\to 2}{lim}\frac{x^7+128}{x+2}$

Answer 1

$\underset{x\to 2}{lim}\frac{x^2+128}{x+2}$

Put the value $x-2$ in equation & solve

$\frac{2^7+128}{2+2}=\frac{2^7+2^7}{4}=\frac{2^7+(1+1)}{4}$

$\frac{2^7\times 2}{4}=2^6=64$