Question

Solve each equation using trial and error method

$3y-2=7$

Answer 1

Solving equation using trial and error method

$y$	$LHS$	$RHS$
$1$	$3y-2=(3\times 1)-2=1$	$7$	$LHS\ne RHS$
$2$	$3y-2=(3\times 2)-2=4$	$7$	$LHS\ne RHS$
$3$	$3y-2=(3\times 3)-2=7$	$7$	$LHS=RHS$
$4$	$3y-2=(3\times 4)-2=10$	$7$	$LHS\ne RHS$

From the table, we find that $LHS=RHS$ , when $y=3$

Hence, the solution of given equation is $y=3$