Question

Solve each of the following equation and also verify your solution:
$\frac{7}{x}+35=\frac{1}{10}$

Answer 1

$$\begin{gathered} \frac{7}{\mathrm{x}}+35=\frac{1}{10} \\ \mathrm{or}\frac{7}{\mathrm{x}}=\frac{1}{10}-35 \\ \mathrm{or}\frac{7}{\mathrm{x}}=\frac{1-350}{10} \\ \mathrm{or}\frac{\mathrm{x}}{7}=\frac{10}{-349} \\ \mathrm{or}\mathrm{x}=\frac{-10\times 7}{349}=\frac{-70}{349} \\ \mathrm{Verification}: \\ \mathrm{L}.\mathrm{H}.\mathrm{S}.=\frac{7}{{\displaystyle \frac{-70}{349}}}+35 \\ =7\times \frac{349}{-70}+35 \\ =\frac{349}{-10}+35=\frac{1}{10}=\mathrm{R}.\mathrm{H}.\mathrm{S}. \end{gathered}$$