Question

Solve each of the following equations by trial and error method:

(i) $x-5=1$

Answer 1

Put different values of $x$ in such a way that L.H.S = R.H.S

Let us put $x=1$ in $x-5$, we have

$1-5=-4$ which is not equal to $1$

So, $x=1$ is not the solution of given equation.

Let us put $x=2$ in $x-5$, we have

$2-5=-3$ which is not equal to $1$

So, $x=2$ is not the solution of given equation.

Let us put $x=6$ in $x-5$, we have

$6-5=1$ which is equal to $1$

So, $x=6$ is the solution of given equation.

Hence, By Hit and trial method $x=6$ is the solution of given equation.