Question

Solve each of the following pairs of equations by the elimination method.
$2x+3y=8$
$4x+6y=7$

Answer 1

$2x+3y=\mathrm{8......}\left(i\right)$

$4x+6y=\mathrm{7......}\left(ii\right)$

Multiply $\left(i\right)$ by $4$

$4x+6y=\mathrm{16......}\left(iii\right)$

LHS of $\left(ii\right)$ and $\left(iii\right)$ are same but RHS is different

Hence the solution does not exist.