Question

Solve each of the following quadratic equations:
$4x^2-2(a^2+b^2)x+a^2{b}^2=0$

Answer 1

a= 4

b= -2(a²+b²)

c= a²b²

Using Discriminant formula,

D= b²-4ac

[-2(a²+b²)]²-4 x4xa²b²

4(a⁴+b⁴+2a²b²)-16a²b²

(2a²-2b²)²

x= (-b±D)/ 2a

x= [2(a²+b²)+2(a²-b²)]/8 = 4a²/8 = a²/2

x= [2(a²+b²)-2(a²-b²)]/8 = 4b²/8 = b²/2