Question

Solve each of the following systems of equations by using the method of cross multiplication:

$7x-2y=3,22x-3y=16.$

Answer 1

$7x-2y=3,22x-3y=16.$

By cross multiplication, we have

$\Rightarrow \frac{x}{(-16–\frac{9}{2})}=\frac{y}{(-33+56)}=\frac{1}{\frac{-21}{2}+22}\Rightarrow \frac{x}{\frac{23}{2}}=\frac{y}{23}=\frac{1}{\frac{23}{2}}\Rightarrow \frac{x}{\frac{23}{2}}=\frac{1}{\frac{23}{2}},\frac{y}{23}=\frac{1}{\frac{23}{2}}$

Hence, x = 1 and y = 2 is the solution.