Solve equations using substitution method:
$2 x - y = 3$ and $4 x + y = 3$

- 1

and

1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

- 2

and

1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1

and

- 1

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

- 1

and

- 1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $1$ and $- 1$
$2 x - y = 3$ ------- (1)
$4 x + y = 3$ ------ (2)
From equation 1 :
$y = 2 x - 3$
Substitute the value of $y$ in equation 2 :
$4 x + y = 3$
$4 x + 2 x - 3 = 3$
$6 x = 3 + 3$
$x = \frac{6}{6} = 1$
Now, Substitute $x = 1$ in equation 1 :
$2 x - y = 3$
$2 (1) - y = 3$
$2 - 3 = y$
$y = - 1$
Therefore the solution is: $x = 1$ and $y = - 1$

Suggest Corrections

Similar questions

Q. Solve equations using substitution method:

3 x + 2 y = 1

and

2 x - 3 y = 5

Q. Solve for x and y by substitution method:

\frac{1}{2 x} + \frac{1}{3 y} = 2 (x \neq 0, y \neq 0) \frac{1}{3 x} + \frac{1}{y} = \frac{11}{3}

Question 1 (iv)
Solve the following pair of linear equations by the elimination method and the substitution method:
$\frac{x}{2} + \frac{2 y}{3} = - 1$ and $x - \frac{y}{3} = 3$

Q. Solve the following pair of Equations by substitution method:

x - y = 1

and

2 x - 3 y = 2

Q. Solve by substitution method

\frac{1}{x} + \frac{1}{y} = 4

and

\frac{2}{x} + \frac{3}{y} = 7, x \neq 0, y \neq 0

Join BYJU'S Learning Program

Solve equations using substitution method:2x−y=3 and 4x+y=3

The correct option is C 1 and −12x−y=3 ------- (1)4x+y=3 ------ (2)From equation 1 :y=2x−3Substitute the value of y in equation 2 : 4x+y=34x+2x−3=36x=3+3x=66=1Now, Substitute x=1 in equation 1 : 2x−y=32(1)−y=32−3=yy=−1Therefore the solution is: x=1 and y=−1

Solve equations using substitution method:
$2 x - y = 3$ and $4 x + y = 3$