Question

Solve following equation by elimination method

$3x+2y=11$

$2x+3y=4$

Answer 1

Given that:

$3x+2y=11,$ ......(1)

On multiplying by $3$, we get

$9x+6y=33$ ......(2)

$2x+3y=4,$ ......(3)

On multiplying by $2$, we get

$4x+6y=8$ ......(4)

On subtracting equation (4) from equation (2), we get

$5x=25,$

$x=5$

Substituting in equation (1), we get

$15+2y=11$

$y=-2$