Question

Solve following system of equations by elimination method. $x+2y=7,x-2y=1$

• A. $(4,\frac{3}{2})$
• B. $(4,\frac{2}{2})$
• C. $(3,\frac{3}{2})$
• D. None of these

Answer 1

Answer: (A)

$(4,\frac{3}{2})$

Given equations are

$x+2y=7$.......(i)

$x-2y=1$.........(ii)

Subtract equation (ii) from (i), we get

$2x=8$

$\Rightarrow x=4$

put value of $x$ in equation (ii)

$4-1=2y$

$3=2y$

$\therefore y=\frac{3}{2}$

$\therefore x=4,y=\frac{3}{2}$