Question

Solve following system of equations by elimination method. $x+\frac{y}{2}=4,\frac{x}{3}+2y=5$

• A. $(3,2)$
• B. $(3,1)$
• C. $(2,2)$
• D. None of these

Answer 1

The correct option is A $(3,2)$

Given equations are

$x+\frac{y}{2}=4$.....(i)

$\frac{x}{3}+2y=5$......(ii)

Multiply equation (i) by 4 we get

$4x+2y=16$....(iii)

Subtract equation (ii) from (iii) we get

$\frac{11}{3}x=11$

$\therefore x=3$

Put value of $x$ in equation (iii)

$(4\times 3)+2y=16$

$\Rightarrow 2y=4$

$\Rightarrow y=2$

$\therefore x=3,y=2$