Question

Solve for $4x+\frac{6}{y}=15$ and $3x-\frac{4}{y}=7$. Hence, find '$a$', if $y=ax-2$.

• A. $\frac{4}{3}$
• B. $-\frac{4}{3}$
• C. $\frac{1}{3}$
• D. $\frac{2}{3}$

Answer 1

The correct option is A $\frac{4}{3}$

Given:

$4x+\frac{6}{y}=15$...(1)

$3x-\frac{4}{y}=7$...(2)

Solving equations (1) and (2) we get values of x and y as:

$x=3$ and $y=2$

$y=ax-2$

$\Rightarrow 2=a\left(3\right)-2$

$\Rightarrow a=\frac{4}{3}$