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Question

Solve for θ if 4cos2θ + 2sinθ – 4 = 0, where 0  θ  90.


  1. 0

  2. 30

  3. both (a) and (b) 

  4. cannot be determined


Solution

The correct option is C

both (a) and (b) 


4cos2θ + 2sinθ – 4 = 0

4[1 - sin2θ] + 2sinθ – 4 = 0

4 - 4sin2θ +  2sinθ – 4 = 0

2sinθ [1 - 2sinθ] = 0

sinθ = 0 or sinθ = 12   
So, θ=0 or θ=30

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