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Solving Inequalities

Solve for x...

Question

Solve for $x$ :
$3 (x + 1) = 12 + 4 (x - 1)$

- 5

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- 2

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7

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3

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Solution

The correct option is A $- 5$
$3 (x + 1) = 12 + 4 (x - 1) 3 x + 3 = 12 + 4 x - 4 - x = 12 - 3 - 4$
$- x = 5$
$∴ x = - 5$

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\frac{2}{3} (4 x - 1) - [4 x - \frac{1 - 3 x}{2}] = \frac{x - 7}{2}

5 x - (4 x - 7) (3 x - 5) = 6 - 3 (4 x - 9) (x - 1)

\frac{5 x + 1}{7} - 4 (x + \frac{2}{5}) \leq 1 \frac{3}{5} + \frac{3 x - 1}{7}, x \in R

Solve the equations:

(i) 5x = 3x + 24;

(ii) 8t + 5 = 2t − 31;

(iii) 7x − 10 = 4x + 11;

(iv) 4z + 3 = 6 + 2z;

(v) 2x − 1 = 14 − x;

(vi) 6x + 1 = 3(x − 1) + 7;

(vii) ;

(viii) ;

(ix) 3(x + 1) = 12 + 4 (x − 1);

(x) 2x − 5 = 3(x − 5);

(xi) 6(1 − 4x) + 7(2 + 5x) = 53;

(xii) 3(x + 6) + 2 (x + 3) = 64;

(xiii) ;

(xiv) .

\frac{3 x + 2}{7} + \frac{4 (x + 1)}{5} = \frac{2}{3} (2 x + 1)

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