Solve for $x$ :
$8 x^{2} + 2 x - 3 = 0$

Open in App

Solution

Given the quadratic equation
$8 x^{2} + 2 x - 3 = 0$
on, $8 x^{2} + 6 x - 4 x - 3 = 0$
on, $2 x (4 x + 3) - 1 (4 x + 3) = 0$
on, $(2 x - 1) (4 x + 3) = 0$
on, $x = 1 / 2, - 3 / 4$

Suggest Corrections

Similar questions

{tan}^{- 1} (\frac{6 x}{1 - 8 x^{2}}) = 0

Solve:- 8 $x^{2}$ + 10x +3 = 0

8 x^{2} - 10 x - 3 = 0

\frac{16 x^{2} - 20 x + 9}{8 x^{2} + 12 x + 21} = \frac{4 x - 5}{2 x + 3}

Solve the following quadratics $8 x^{2} - 9 x + 3 = 0$

Join BYJU'S Learning Program