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Solving Simultaneous Linear Equation Using Cramer's Rule

Solve for x a...

Question

Solve for x and y

2/x+3/y=9/xy and 4/x+9/y=21/xy(x≠0 and y≠0)

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Solution

Multiplying both sides by xy, we get :
2y+3x=9
4y+9x =21
Now, multiplying the first equation by (2) and subtracting from the second one, we get :
(4y+9x)-2(2y+3x)=21-9*2
3x=21-18
X=1
Hence, substituting the value in either equation and solving for y, we get :
2y+3=9
2y=6
y=3

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Similar questions

x

y

\frac{2}{x} + \frac{3}{y} = \frac{9}{x y}

\frac{4}{x} + \frac{9}{y} = \frac{21}{x y}

Q. Solve the following systems of equations:

\frac{2}{x} + \frac{3}{y} = \frac{9}{x y}

\frac{4}{x} + \frac{9}{y} = \frac{21}{x y}, x \neq 0, y \neq 0

\frac{2}{x} + \frac{3}{y} = \frac{9}{x y}

\frac{4}{x} + \frac{9}{y} = \frac{21}{x y}

x \neq 0, y \neq 0

, the values of x and y are, respectively.

\frac{2}{x} + \frac{3}{y} = \frac{9}{x y}

\frac{4}{x} + \frac{9}{y} = \frac{21}{x y}

x \neq 0, y \neq 0

, then the values of

x

y

Solve for x and y:

$4 x + 6 y = 3 x y, 8 x + 9 y = 5 x y (x \neq 0, y \neq 0) .$

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