Question

Solve for $x$ and $y$:
$4x+\frac{6}{y}=15;3x-\frac{4}{y}=7$

Answer 1

$4x+\frac{6}{y}=15$ $3x-\frac{4}{y}=7$

$12x+\frac{18}{y}=45$___(1) $12x-\frac{16}{y}=28$___(2)

$\Rightarrow Eq\left(1\right)-\left(2\right)$

$\frac{18}{y}+\frac{16}{y}=17$

$34/y=17$

$y=2$ $3x-2=7$

$x=3$