Question

Solve for $x$ and $y$:
$4x+\frac{6}{y}=15$ ; $3x-\frac{4}{y}=7$

• A. $x=1,y=2$
• B. $x=1,y=1$
• C. $x=2,y=2$
• D. none of the above

Answer 1

The correct option is D none of the above

Given equations are

$4x+\frac{6}{y}=15$ ------equation$\left(1\right)$

$3x-\frac{4}{y}=7$ --------equation$\left(2\right)$

From equation $\left(1\right)$ and equation $\left(2\right)$ can be written as

$4xy+6=15y$ -----equation$\left(3\right)$

$3xy-4=7y$ ------equation$\left(4\right)$

Multiplying equation$\left(3\right)$ by $3$ and equation$\left(4\right)$ by $4$ and subtracting

$12xy+18=45y$

$12xy-16=28y$

After solving, we get $y=2$

From equation$\left(1\right)$,

$4x+\frac{6}{y}=15$ --------equation$\left(1\right)$

$4x=12$

$x=3,y=2$