Question

Solve for x and y:

$\frac{x+y-8}{2}=\frac{x+2y-14}{3}=\frac{3x+y-12}{11}$

Answer 1

$\frac{x+y-8}{2}=\frac{x+2y-14}{3}=\frac{3x+y-12}{11}$

$\frac{x+y-8}{2}=\frac{x+2y-14}{3}$ Simplify :
$3x+3y-24=2x+4y-28$
$x-y+4=0$---- (1)

$\frac{x+y-8}{2}=\frac{3x+y-12}{11}$ SImplify :
$6x+2y-24=11x+11y-88$
$5x+9y-64=0$---- (2)

Multiply by 5 in equ 1

$5x-5y+20=0$---- (3 )

Subtract equ (3) from (2)
$14y-84=0$
$y=\frac{84}{14}=6$
$y=6$ put in equation 1
$x-6+4=0$
$x=2$

$x=2andy=6$