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Question

Solve for x and y if (y2x2)+2(3y2x)=3(37)

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Solution

(y2x2)+2(3y2x)=3(37)
(y2x2)+(6y4x)=(921)
(y2+6yx2+4x)=(921)

Equating corresponding elements of equal matrices, we get
x2+4x=21
x2+4x21=0
x2+7x3x21=0
x(x+7)3(x+7)=0
(x+7)(x3)=0
x=7,3
y2+6y=9
y2+6y+9=0
(y+3)2=0
y+3=0
y=3

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